26x^2-23x+5=0

Solution for 26x^2-23x+5=0 equation:

26x^2-23x+5=0

a = 26; b = -23; c = +5;
Δ = b2-4ac
Δ = -232-4·26·5
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-3}{2*26}=\frac{20}{52}
=5/13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+3}{2*26}=\frac{26}{52}
=1/2
$